WEBVTT 00:00.950 --> 00:06.980 Hello everybody and welcome to this solution off our Python standard library assessment quiz. 00:07.040 --> 00:13.850 So this Chris covers all topics of our basic section and if you master the Chris you can be sure that 00:13.850 --> 00:17.030 you will also have no problems with our case study. 00:17.030 --> 00:21.920 The second album challenge and actually then you can skip the whole basic section here. 00:23.180 --> 00:29.060 So the Chris has the 15 questions and of course the that easy questions and also harder more tricky 00:29.060 --> 00:30.340 questions. 00:30.470 --> 00:33.380 And if you do not have all 50 questions correct. 00:33.380 --> 00:40.040 So that's no problem as long as you can follow my solutions and think Okay I understand what the guy 00:40.040 --> 00:42.360 is trying to telling me here actually. 00:42.500 --> 00:42.680 Yeah. 00:42.680 --> 00:48.280 Then in this case you should be best prepared for the case study. 00:48.650 --> 00:50.110 So let's start our Chris 00:53.220 --> 00:54.810 a.m. The first question we have. 00:54.850 --> 00:58.190 Uh two two objects 3 and 7. 00:58.270 --> 01:04.130 And we assign the variable a two three and the variable B to seven. 01:04.420 --> 01:11.140 And if we add a and b Of course we get 10 so no surprise we can add integers and we use python as a 01:11.140 --> 01:11.970 calculator. 01:12.640 --> 01:14.200 So the correct answer is 10 01:19.600 --> 01:20.410 question 2. 01:20.440 --> 01:26.620 So the key message here is that you cannot add a string object with an integer like here in the first 01:26.620 --> 01:33.410 two answers so you can only add a string and string of its concatenated so the two strings and then 01:33.450 --> 01:35.550 we do not have this case here as an answer. 01:35.560 --> 01:42.460 And of course we can add two integers as we have here in this case so printing four plus six gives us 01:42.500 --> 01:45.860 10 so we do not get an error message here 01:50.420 --> 01:56.560 here we create a three copies of the string Hello World and are simply concatenated so the correct answer 01:56.560 --> 01:57.530 is here. 01:57.540 --> 01:58.140 This one 02:08.360 --> 02:10.580 here we have a list of the three elements. 02:10.580 --> 02:16.430 And if we multiply a list in that we have the key message here is and that follows. 02:16.450 --> 02:18.710 So that's no element y's operation. 02:18.860 --> 02:25.100 So actually we do not get multiplied elements like here and then this answer you ever you get um three 02:25.110 --> 02:29.060 maybe by Platt by three six multiplied by three and so on. 02:29.060 --> 02:31.010 But this is not how lists work. 02:31.070 --> 02:35.040 And actually we get to three times the copy off our list concatenate. 02:35.060 --> 02:42.930 So this is all a correct answer here. 02:42.990 --> 02:48.150 Here we have them the same list and all three options and then paste and we have the so-called zero 02:48.150 --> 02:53.970 based indexing saw fear fear a list we are starting at the index position zero. 02:53.980 --> 03:05.690 So the integer 2 has the index position zero and then we have one two three four five and six so consequently 03:05.750 --> 03:11.840 we are of a cat in our slice so kept us at index position 0 1 2. 03:11.880 --> 03:19.130 Was also want to have them three four including so we have the indexed positions two to four including 03:19.130 --> 03:19.410 the. 03:19.430 --> 03:23.940 We have to slice for two to five excluding. 03:23.990 --> 03:25.930 So this is the correct answer here 03:34.320 --> 03:39.100 so end this question to answer is actually a slice for the last two elements. 03:39.110 --> 03:46.700 So elephant and six point two and one does not so he and the first option we slice from minus two until 03:46.700 --> 03:48.530 the very last element. 03:48.540 --> 03:56.150 So alternatively to the zero base and next thing we can also index from minus one minus to minus three 03:56.150 --> 03:57.380 and so on. 03:57.560 --> 04:07.320 So minus two with Elif and until the very last element including So the first answer is correct then 04:07.320 --> 04:17.400 the second answer slices from the fifth element or the element at an exposition 5 0 1 2 3 4 5. 04:17.400 --> 04:20.570 It's elephant until the very last including. 04:20.850 --> 04:28.840 So this answer also slices at the very last elements and only here the last answer It slices only elephant. 04:28.950 --> 04:31.800 So in exposition 6 thus excluding 04:37.620 --> 04:43.190 this question here we have an example of in comparison operators so we have exclamation mark equal. 04:43.990 --> 04:47.690 And this checks if 10 is not equal to 9. 04:47.700 --> 04:50.090 And this is true. 04:50.340 --> 05:02.600 And if we apply not to uh gives us false so false is the correct answer here. 05:02.620 --> 05:06.340 Here we check whether dark in quotation mark is a string. 05:06.410 --> 05:09.180 And yes it's a string. 05:09.310 --> 05:13.660 And further we check whether 10 is greater than 8 and this is also true. 05:14.230 --> 05:21.600 And here we have one logical operator and and we only get a true here if all conditions are true. 05:21.610 --> 05:24.620 So dark is a string and time is greater than 8. 05:24.620 --> 05:32.340 And this is the case so we should get a true here. 05:32.370 --> 05:37.610 Here we have an if statement and at the end of this statement We need a colon. 05:37.650 --> 05:44.360 So here we have a colon and he also and after the statement we have to make and then to define the action 05:44.370 --> 05:45.240 we want to take. 05:45.240 --> 05:52.830 If the condition is correct and and does it automatically if you press enter after the if statement 05:53.430 --> 05:59.340 so he and this answer we do not have an intent here for for the print statement and therefore the only 05:59.490 --> 06:02.820 answer that we have a colon and an intent C at this one 06:10.520 --> 06:16.850 here we want to create a list of square numbers from 1 to 10 including and here we have the range object 06:17.350 --> 06:22.700 in the range object by default starts with 0 and the end value as exclusive. 06:22.820 --> 06:31.050 So this answer would give us some clear numbers from 0 to 9 including And the second key message of 06:31.050 --> 06:38.580 this question here is that also after a false statement or in the for loop we have to make a colon and 06:38.580 --> 06:51.190 an indent and here we do not have an intent so the only correct answer is this one here. 06:51.240 --> 06:58.230 Here we have a list of seven names and we want to create a list a names where all the names beginning 06:58.230 --> 07:03.750 with a name are included and only the names beginning with a. 07:03.820 --> 07:06.210 So the question is here we have three codes. 07:06.220 --> 07:12.670 And the question is how many of these codes do the job and the answer is actually that all three codes 07:12.700 --> 07:13.410 work. 07:13.480 --> 07:21.250 So here in the first code we iterate over the names and the first letter of the name is an A. 07:21.280 --> 07:24.180 We append the name to our names list. 07:24.370 --> 07:25.550 So this works. 07:25.690 --> 07:31.570 And the second code does actually the same chop in a list comprehension so we create here a list and 07:31.570 --> 07:37.090 for each name in the name lists we check if the first letter an A and if it is an A. 07:37.090 --> 07:39.820 We append the name into the list. 07:39.820 --> 07:46.050 So this works this letter and in code 3 it is a somewhat tricky one. 07:46.050 --> 07:51.580 So we first of all sort the names lists so the lists are starting with the names beginning with a. 07:52.500 --> 07:58.900 And then we are introducing a by loop and iterating over all indexed positions starting from an exposition 07:58.920 --> 08:00.300 zero of our list. 08:01.950 --> 08:09.990 And as long as the first letter isn't a We append the name to our lists and we increase the index position 08:10.050 --> 08:13.080 by 1 and check the next name. 08:13.080 --> 08:21.180 So this was actually a quite tricky question and the correct answers is three. 08:21.380 --> 08:21.770 All right. 08:21.780 --> 08:29.520 So here we have a list with integers from 1 to 20 and we want to create a new list that contains all 08:29.520 --> 08:36.390 elements of the list that are divisible by three of us out remainder and all other elements would be 08:36.390 --> 08:37.890 stored in another list. 08:37.930 --> 08:41.300 And and that's another condition here. 08:41.310 --> 08:44.400 So the element 3 must not be in any of the new lists. 08:44.400 --> 08:51.600 So actually 3 is actually divisible by three without remainder but it should not be in our list at all. 08:52.770 --> 08:55.090 Let's have a look at the options here. 08:57.310 --> 09:01.750 So actually the answers are from here on are identical. 09:02.530 --> 09:07.530 So if our element is divisible by three we attended to the list. 09:07.540 --> 09:14.950 Uh and as we appended to the list M however the key message is that first of all we have to check whether 09:14.950 --> 09:19.310 we have the element three in our list so. 09:19.380 --> 09:22.290 If this is the case we have to ignore three. 09:22.320 --> 09:24.970 This the keyboard argument continue. 09:24.990 --> 09:27.530 So here if you come to three in our list. 09:27.630 --> 09:32.730 We just ignore three and go on lists then the next element four. 09:33.090 --> 09:34.800 So this is correct. 09:34.800 --> 09:37.250 And here we do not check if we have three. 09:37.250 --> 09:41.160 So actually I would expect to have and three in our list. 09:41.180 --> 09:45.810 L And here we are checking if we have three in our list. 09:45.810 --> 09:47.900 But if we have three we break. 09:47.910 --> 09:50.070 So we completely break the for loop. 09:50.070 --> 09:54.300 So after the first three elements our iteration stops here. 09:54.780 --> 09:57.860 So the correct answer is um the first one 10:04.970 --> 10:11.780 here we define the function division and we have two arguments of the function A and B and B has an 10:11.810 --> 10:17.210 defined parameter equals 1 and the function returns a divided by B. 10:17.240 --> 10:25.640 So if we call the function by just passing 5 so 5 stands for our argument a and for B we have the default 10:25.640 --> 10:26.590 parameter 1. 10:26.600 --> 10:33.670 If you do not set a concrete parameter by calling our function so we saw tests 5 divided by 1. 10:33.710 --> 10:36.020 So this should be the correct answer. 10:39.570 --> 10:45.590 So here we want to create a function that returns to the sum of randomly generated integers and they 10:45.580 --> 10:53.580 interpret the 1 to 10 and we want to be able to set the size of the randomly generated integers as a 10:53.670 --> 10:56.410 monumental parameter off the function. 10:56.520 --> 10:59.270 So we have here two key messages. 10:59.270 --> 11:06.180 So first of all you want to create random integers in range 1 to 10 and answer 2 and 3 do exactly this 11:06.630 --> 11:11.040 but answer 1 creates the random float in range 0 to 1. 11:11.040 --> 11:18.210 So this is not correct and then Option 2 and 3 we can pass a parameter size. 11:18.210 --> 11:23.360 However if we have a look at the function body so he can answer 3. 11:23.360 --> 11:26.070 We have the concrete size 100. 11:26.150 --> 11:33.640 So even if we change the size and then the function header we always get a size of hundred random integers. 11:33.650 --> 11:36.340 And therefore here. 11:36.650 --> 11:38.300 So number 2 is correct. 11:38.300 --> 11:42.830 So here we are able to define the number of random integers we want to create 11:50.450 --> 11:50.800 all right. 11:50.810 --> 11:58.190 So last question here we have a say it's men and with say it's low we have 700 in 2010 900 say it's 11:58.190 --> 12:05.210 in two thousand eleven and so on and we want to create a line plot to visualize ourselves and we want 12:05.210 --> 12:16.400 to have the Yes on the x axis and the states on the y axis and we have to implement plot live here and 12:16.400 --> 12:22.440 the first answer I guess that's actually a scatter blood another line plot so this is not correct and 12:22.440 --> 12:29.920 here the function party plot we have we have to define as the first argument on the x axis so we have 12:29.950 --> 12:37.650 yes and as the second argument say is so answer 3 is actually the way around and therefore we have to 12:37.650 --> 12:39.120 choose answer to.